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26x-x^2=144
We move all terms to the left:
26x-x^2-(144)=0
We add all the numbers together, and all the variables
-1x^2+26x-144=0
a = -1; b = 26; c = -144;
Δ = b2-4ac
Δ = 262-4·(-1)·(-144)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-10}{2*-1}=\frac{-36}{-2} =+18 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+10}{2*-1}=\frac{-16}{-2} =+8 $
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